Question

A real inverted image in a concave mirror is represented by graph ( $\text{u},\text{v},\text{f}$ are coordinates)

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

For real inverted image formed by concave mirror.
$\text{v}=-\text{v}\text{e},\text{u}=-\text{v}\text{e},\text{f}=-\text{v}\text{e}$
$\Rightarrow \frac{u}{f}$ & $\frac{v}{f}$ are positive
So graph show be in 1st qudarant
$\text{and}\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$
$\Rightarrow \frac{\text{f}}{\text{v}}+\frac{\text{f}}{\text{u}}=1$
This graph can also be realized by Newtons formula ${\text{x}}_1{\text{x}}_2={\text{f}}^2$ where ${\text{x}}_1\text{,}\text{ and }{\text{x}}_2$ are distance from focus so graph will be rectangular hyperbola
$\Rightarrow$ (1) is right answer.