A reaction proceeds by first order, 75 % of this reaction was completed in 32 min. The time required for 50 % completion is

Question

A reaction proceeds by first order, 75 % of this reaction was completed in 32 min. The time required for 50 % completion is (A)  8 min  (B)  16 min  (C)  20 min  (D)  24 min

Tardigrade Admin · Accepted Answer

For first order reaction k=(2.303/t) log10 (a/(a-x)) where, a = Initial concentration x = change in concentration during time âtâ. If 75 % of the reaction was completed in 32 min,then k=(2.303/32)log10 (100/(100-75)) =(2.303/32) log10 4 k=0.0433 min-1 Hence, time required for the completion of 50 % reaction t=(2.303/0.0433) log10 (100/(100-50)) =(2.303/0.0433) log102 =16 min

Q. A reaction proceeds by first order, $75%$ of this reaction was completed in $32$ min. The time required for $50%$ completion is

$8 min$

$16 min$

$20 min$

$24 min$

Q. A reaction proceeds by first order, 75% of this reaction was completed in 32 min. The time required for 50% completion is

8min

16min

20min

24min

Q. A reaction proceeds by first order, $75%$ of this reaction was completed in $32$ min. The time required for $50%$ completion is

$8 min$

$16 min$

$20 min$

$24 min$