A ray of light is incident at an angle of, incidence 60° from air to liquid. What is the 1 ratio of width from air to liquid if angle of refraction is 45° ?

Question

A ray of light is incident at an angle of, incidence 60° from air to liquid. What is the 1 ratio of width from air to liquid if angle of refraction is 45° ? (A)  (√2/3)  (B)  √(3/2)  (C)  √(2/3)  (D)  (1/√2)

Tardigrade Admin · Accepted Answer

( textWidth of incident wavefront/ textWidth of refracted wavefront)=( cos i/ cos r) =( cos 60° / cos 45° )=(1/2/1/√2) =(1/√2)

Q. A ray of light is incident at an angle of, incidence $60^{\circ}$ from air to liquid. What is the 1 ratio of width from air to liquid if angle of refraction is $45^{\circ}$ ?

$\frac{2}{3}$

$\frac{3}{2}$

$\frac{2}{3}$

$\frac{1}{2}$

$\frac{Width of incident wavefront}{Width of refracted wavefront} = \frac{c o s i}{c o s r}$ $= \frac{c o s 60 ^{\circ}}{c o s 45 ^{\circ}} = \frac{1/2}{1/ 2}$ $= \frac{1}{2}$

Q. A ray of light is incident at an angle of, incidence 60∘ from air to liquid. What is the 1 ratio of width from air to liquid if angle of refraction is 45∘ ?

32​​

23​​

32​​

2​1​

Width of refracted wavefrontWidth of incident wavefront​=cosrcosi​ =cos45∘cos60∘​=1/2​1/2​ =2​1​

Q. A ray of light is incident at an angle of, incidence $60^{\circ}$ from air to liquid. What is the 1 ratio of width from air to liquid if angle of refraction is $45^{\circ}$ ?

$\frac{2}{3}$

$\frac{3}{2}$

$\frac{2}{3}$

$\frac{1}{2}$

$\frac{Width of incident wavefront}{Width of refracted wavefront} = \frac{c o s i}{c o s r}$ $= \frac{c o s 60 ^{\circ}}{c o s 45 ^{\circ}} = \frac{1/2}{1/ 2}$ $= \frac{1}{2}$