Q.
A ray of light falls normally on one face of prism of refractive index 2 and comes out at grazing emergence from the second surface. The angle of prism is
3175
211
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Solution:
Let angle of prism be A
As the ray of light falls normally on the first face of prism, therefore i1=0
Applying Snell's law at the first face, we get 1sini1=μsinr1 ∴r1=0
For a prism r1+r2=A A=r2
Applying Snell's law at the second face, we get μsinr2=1sine
where e is the angle of emergence μsinr2=1sin90∘ (From figure) sinr2=μ1 r2=sin−1(21) r2=45∘ ∴A=45∘ (From (i))