A ray of light along x+√ 3 y=√ 3 gets reflected upon reaching x -axis, the equation of the reflected ray is

Question

A ray of light along x+√ 3 y=√ 3 gets reflected upon reaching x -axis, the equation of the reflected ray is (A) y=x+ √ 3 (B) √ 3 y=x- √ 3 (C) y=√ 3x-√ 3 (D) √ 3y=x-1

Tardigrade Admin · Accepted Answer

Take any point B (0,1) on given line. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/96bacfd3c465c0e52679a4597ba1e3d7-.png" /> Equation of AB' is y-0= (-1-0/0-√ 3)(x-√ 3) ⇒ -√ 3y=-x+ √ 3 ⇒ x- √ 3 y= √ 3 ⇒ √ 3y=x- √ 3

Q. A ray of light along $x + 3 y = 3$ gets reflected upon reaching $x$ -axis, the equation of the reflected ray is

$y = x + 3$

$3 y = x - 3$

$y = 3 x - 3$

$3 y = x - 1$

Take any point $B (0, 1)$ on given line.

Equation of $A B^{'}$ is
$y - 0 = \frac{- 1 - 0}{0 - 3} (x - 3)$
$\Rightarrow - 3 y = - x + 3$
$\Rightarrow x - 3 y = 3$
$\Rightarrow 3 y = x - 3$

Q. A ray of light along x+3​y=3​ gets reflected upon reaching x -axis, the equation of the reflected ray is

y=x+3​

3​y=x−3​

y=3x​−3​

3​y=x−1