A pure Ge specimen is doped with Al. The number density of acceptor atoms is approximately 1021 m-3. If density of electron hole pair in an intrinsic semiconductor is approximately 1019 m-3, the number density of electrons in the specimen is

Question

A pure Ge specimen is doped with Al. The number density of acceptor atoms is approximately 1021 m-3. If density of electron hole pair in an intrinsic semiconductor is approximately 1019 m-3, the number density of electrons in the specimen is (A) 104 m-3 (B) 102 m-3 (C) 1017 m-3 (D) 1015 m-3

Tardigrade Admin · Accepted Answer

Given that, the density of electron hole pair in an intrinsic semiconductor (ni) =(1019/m3) density of holes (nh) =(1021/m3) We know that nh ⋅ ne =ni2 ∴ 1021 × ne =(1019)2 ⇒ ne =(1019 × 1019/1021) =1017m-3

Q. A pure Ge specimen is doped with $A l$ . The number density of acceptor atoms is approximately $1 0^{21} m^{- 3}$ . If density of electron hole pair in an intrinsic semiconductor is approximately $1 0^{19} m^{- 3}$ , the number density of electrons in the specimen is

$1 0^{4} m^{- 3}$

$1 0^{2} m^{- 3}$

$1 0^{17} m^{- 3}$

$1 0^{15} m^{- 3}$

Q. A pure Ge specimen is doped with Al. The number density of acceptor atoms is approximately 1021m−3. If density of electron hole pair in an intrinsic semiconductor is approximately 1019m−3, the number density of electrons in the specimen is

104m−3

102m−3

1017m−3

1015m−3

Given that, the density of electron hole pair in an intrinsic semiconductor (ni​)=m31019​ density of holes (nh​)=m31021​ We know that nh​⋅ne​=ni2​ ∴1021×ne​=(1019)2 ⇒ne​=10211019×1019​ =1017m−3

Q. A pure Ge specimen is doped with $A l$ . The number density of acceptor atoms is approximately $1 0^{21} m^{- 3}$ . If density of electron hole pair in an intrinsic semiconductor is approximately $1 0^{19} m^{- 3}$ , the number density of electrons in the specimen is

$1 0^{4} m^{- 3}$

$1 0^{2} m^{- 3}$

$1 0^{17} m^{- 3}$

$1 0^{15} m^{- 3}$