A proton travelling at 23° C w.r.t. the direction of a magnetic field of strength 2.6 mT experiences a magnetic force of 6.5× 10-17N . What is the speed of the proton?

Question

A proton travelling at 23° C w.r.t. the direction of a magnetic field of strength 2.6 mT experiences a magnetic force of 6.5× 10-17N . What is the speed of the proton? (A)  2× 105 text m/s  (B)  4× 105 text m/s  (C)  6× 105 text m/s  (D)  6× 10-5 text m/s

Tardigrade Admin · Accepted Answer

F=qvB sin θ v=(F/qB sin θ ) =(6.5× 10-17/26× 10-3× 1.6× 10-19× 0.39) v=4× 105m/s

Q. A proton travelling at $23^{\circ} C$ w.r.t. the direction of a magnetic field of strength 2.6 mT experiences a magnetic force of $6.5 \times 10^{- 17} N$ . What is the speed of the proton?

$2 \times 10^{5} m / s$

$4 \times 10^{5} m / s$

$6 \times 10^{5} m / s$

$6 \times 10^{- 5} m / s$

$F = q v B sin θ$ $v = \frac{F}{qB s i n θ}$ $= \frac{6.5 \times 10 ^{- 17}}{26 \times 10 ^{- 3} \times 1.6 \times 10 ^{- 19} \times 0.39}$ $v = 4 \times 10^{5} m / s$

Q. A proton travelling at 23∘C w.r.t. the direction of a magnetic field of strength 2.6 mT experiences a magnetic force of 6.5×10−17N . What is the speed of the proton?

2×105m/s

4×105m/s

6×105m/s

6×10−5m/s