A proton is projected with velocity vecv=2 hati in a region where magnetic field vecB=( hati+3 hatj+4 hatk) μ T and electric field vecE=10 hati μ V m-1. Then find out the net acceleration of proton:

Question

A proton is projected with velocity vecv=2 hati in a region where magnetic field vecB=( hati+3 hatj+4 hatk) μ T and electric field vecE=10 hati μ V m-1. Then find out the net acceleration of proton: (A) 1400 ms-2 (B) 700 ms-2 (C) 1000 ms-2 (D) 800 ms-2

Tardigrade Admin · Accepted Answer

vecF=Q vecE+Q( vecV × vecB) vecF=1.6 × 10-19 × 10 hati × 10-6+1.6 × 10-19[(2 hati) ×( hati+3 hatj+4 hatk)] × 10-6 vecF=1.6 × 10-19[10 hati+6 hatk-8 hatj] × 10-6 vecF=1.6 × 10-19[10 hati-8 hatj+6 hatk] × 10-6 N veca=1.6 × 10-19[10 hati-8 hatj+6 hatk] × 10-6 / 1.6 × 10-27 m / s 2 1400 m / s 2

Q. A proton is projected with velocity $v = 2 \hat{i}$ in a region where magnetic field $B = (\hat{i} + 3 \hat{j} + 4 \hat{k}) μ T$ and electric field $E = 10 \hat{i} μ V m^{- 1}$ . Then find out the net acceleration of proton:

1400 $m s^{- 2}$

700 $m s^{- 2}$

1000 $m s^{- 2}$

800 $m s^{- 2}$

Q. A proton is projected with velocity v=2i^ in a region where magnetic field B=(i^+3j^​+4k^)μT and electric field E=10i^μVm−1. Then find out the net acceleration of proton:

1400 ms−2

700 ms−2

1000 ms−2

800 ms−2

F=QE+Q(V×B) F=1.6×10−19×10i^×10−6+1.6×10−19[(2i^)×(i^+3j^​+4k^)]×10−6 F=1.6×10−19[10i^+6k^−8j^​]×10−6 F=1.6×10−19[10i^−8j^​+6k^]×10−6N a=1.6×10−19[10i^−8j^​+6k^]×10−6/1.6×10−27m/s2 1400m/s2

Q. A proton is projected with velocity $v = 2 \hat{i}$ in a region where magnetic field $B = (\hat{i} + 3 \hat{j} + 4 \hat{k}) μ T$ and electric field $E = 10 \hat{i} μ V m^{- 1}$ . Then find out the net acceleration of proton:

1400 $m s^{- 2}$

700 $m s^{- 2}$

1000 $m s^{- 2}$

800 $m s^{- 2}$