A proton, a deuteron and an α-particle accelerated through the same potential difference enter a region of uniform magnetic field, moving at right angles to B. What is the ratio of their K.E.?

Question

A proton, a deuteron and an α-particle accelerated through the same potential difference enter a region of uniform magnetic field, moving at right angles to B. What is the ratio of their K.E.? (A) 2: 1: 1 (B) 2: 2: 1 (C) 1: 2: 1 (D) 1: 1: 2

Tardigrade Admin · Accepted Answer

K.E. gained by charged particle of charge q when accelerated under a potential difference

V

will be

E_{k} = q V

For a given

V, E_{k} \propto q

For proton, deuteron and

α

-particle, the ratio of charges is 1 : 1 : 2.

Q. A proton, a deuteron and an $α$ -particle accelerated through the same potential difference enter a region of uniform magnetic field, moving at right angles to $B$ . What is the ratio of their K.E.?

2 : 1 : 1

2 : 2 : 1

1 : 2 : 1

1 : 1 : 2

K.E. gained by charged particle of charge q when accelerated under a potential difference $V$ will be $E_{k} = q V$
For a given $V, E_{k} \propto q$
For proton, deuteron and $α$ -particle, the ratio of charges is 1 : 1 : 2.

Q. A proton, a deuteron and an α-particle accelerated through the same potential difference enter a region of uniform magnetic field, moving at right angles to B. What is the ratio of their K.E.?