A power transmission line feeds input power at 2300 V to a step down transformer with its primary windings having 4000 turns, giving the output power at 230 V. If the current in the primary of the transformer is 5 A, and its efficiency is 90 %, the output current would be :

Question

A power transmission line feeds input power at 2300 V to a step down transformer with its primary windings having 4000 turns, giving the output power at 230 V. If the current in the primary of the transformer is 5 A, and its efficiency is 90 %, the output current would be : (A) 50 A (B) 45 A (C) 25 A (D) 20 A

Tardigrade Admin · Accepted Answer

We know that, efficiency is given by η=( text output power/ text input ower ) =(E s ⋅ I s /E p ⋅ I p ) Here, η=90 %, E p =2300 V , I p =5 A and E s =230 V Therefore, (90/100) =(230 × I s /2300 × 5) I s =(90 × 2300 × 5/230 × 100)=45 A

Q. A power transmission line feeds input power at $2300 V$ to a step down transformer with its primary windings having $4000$ turns, giving the output power at $230 V$ . If the current in the primary of the transformer is $5 A$ , and its efficiency is $90%$ , the output current would be :

$50 A$

$45 A$

$25 A$

$20 A$

Q. A power transmission line feeds input power at 2300V to a step down transformer with its primary windings having 4000 turns, giving the output power at 230V. If the current in the primary of the transformer is 5A, and its efficiency is 90%, the output current would be :

50A

45A

25A

20A

We know that, efficiency is given by η= input ower output power​ =Ep​⋅Ip​Es​⋅Is​​ Here, η=90%,Ep​=2300V,Ip​=5A and Es​=230V Therefore, 10090​=2300×5230×Is​​ Is​=230×10090×2300×5​=45A

Q. A power transmission line feeds input power at $2300 V$ to a step down transformer with its primary windings having $4000$ turns, giving the output power at $230 V$ . If the current in the primary of the transformer is $5 A$ , and its efficiency is $90%$ , the output current would be :

$50 A$

$45 A$

$25 A$

$20 A$