A potential barrier of 0.50 V exists in a p-n junction, If the depletion region is 5.0 × 10-7 m thick, what is i the electric field in this region?

Question

A potential barrier of 0.50 V exists in a p-n junction, If the depletion region is 5.0 × 10-7 m thick, what is i the electric field in this region? (A) 106 V/m (B) 107 V/m (C) 105 V/m (D) 104 V/m

Tardigrade Admin · Accepted Answer

Electric field, E = (V/d) =(0.50 V/5.0 × 10-7 m) =1.0× 106 Vm-1

Q. A potential barrier of $0.50 V$ exists in a $p - n$ junction, If the depletion region is $5.0 \times 1 0^{- 7} m$ thick, what is i the electric field in this region?

$1 0^{6} V / m$

$1 0^{7} V / m$

$1 0^{5} V / m$

$1 0^{4} V / m$

Electric field,
$E = \frac{V}{d}$
$= \frac{0.50 V}{5.0 \times 1 0 ^{- 7} m}$
$= 1.0 \times 1 0^{6} V m^{- 1}$

Q. A potential barrier of 0.50V exists in a p−n junction, If the depletion region is 5.0×10−7m thick, what is i the electric field in this region?

106V/m

107V/m

105V/m

104V/m