Q.
A positive charge Q is uniformly distributed along a circular ring of radius R. A small test charge q is placed at the centre of the ring as shown in figure. Then
At the centre of the ring, E=0 when a positive charge q>0 is displaced away from the centre in the plane of the ring, say to the right, force of repulsion on q, due to charge on right half increases and due to charge on left half decreases. Therefore, charge q is pushed back towards the centre. So option (a) is correct. When charge q is negative (q<0), force is of attraction.
Therefore, charge q displaced to the right continues moving to the right till it hits the ring. Along the axis of the ring, at a distance r from the centre. E=4πε0(r2+a2)3/2Qr
If charge q is negative (q<0), it will perform SHM for small displacement along the axis.