A point on the periphery of a rotating disc has its acceleration vector making an angle 30° with the velocity vector. Then, the ratio of the magnitude of centripetal acceleration to the tangential acceleration is

Question

A point on the periphery of a rotating disc has its acceleration vector making an angle 30° with the velocity vector. Then, the ratio of the magnitude of centripetal acceleration to the tangential acceleration is (A) sin30°  (B) cos30°  (C) tan30°  (D) none of these

Tardigrade Admin · Accepted Answer

tan θ = (aN/at) <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-ttczhvnaktmg.png" />

Q. A point on the periphery of a rotating disc has its acceleration vector making an angle $3 0^{\circ}$ with the velocity vector. Then, the ratio of the magnitude of centripetal acceleration to the tangential acceleration is

$s in 3 0^{\circ}$

$cos 3 0^{\circ}$

$t an 3 0^{\circ}$

none of these

$t an θ = \frac{a _{N}}{a _{t}}$

Q. A point on the periphery of a rotating disc has its acceleration vector making an angle 30∘ with the velocity vector. Then, the ratio of the magnitude of centripetal acceleration to the tangential acceleration is

sin30∘

cos30∘

tan30∘