A point object O is placed in front of a glass rod having spherical end of radius of curvature 30 cm. The image would be formed at .

Question

A point object O is placed in front of a glass rod having spherical end of radius of curvature 30 cm. The image would be formed at . (A) 30 cm left (B) infinity (C) 1 cm to the right (D) 18 cm to the left

Tardigrade Admin · Accepted Answer

beginarrayl μ1( text air )=1 μ2 text (glass) =1.5 u =-15 cm R =30 cm (μ2-μ1/1.5-1)=(μ2/ v )-(μ1/4) (1.5/30)-(1/15) v =-30 endarray Ans. 30 cm towards the left.

Q. A point object O is placed in front of a glass rod having spherical end of radius of curvature 30cm. The image would be formed at .

30 cm left

infinity

1 cm to the right

18 cm to the left

<br/><br/>μ1​( air )=1<br/>μ2​ (glass) =1.5<br/>u=−15cm<br/>R=30cm<br/>1.5−1μ2​−μ1​​=vμ2​​−4μ1​​<br/>301.5​−151​<br/>v=−30<br/>​<br/> Ans. 30cm towards the left.

Q. A point object $O$ is placed in front of a glass rod having spherical end of radius of curvature $30 c m$ . The image would be formed at .