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Question
Physics
A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth's surface is 11 kms -1, the escape velocity from the surface of the planet would be
Q. A planet in a distant solar system is
10
times more massive than the earth and its radius is
10
times smaller. Given that the escape velocity from the earth's surface is
11
km
s
−
1
, the escape velocity from the surface of the planet would be
2754
192
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A
1.1
km
s
−
1
B
11
km
s
−
1
C
110
km
s
−
1
D
0.11
km
s
−
1
Solution:
(
v
e
)
e
(
v
e
)
p
=
R
e
2
G
M
e
R
p
2
G
M
p
=
M
e
M
p
×
R
p
R
e
=
M
e
10
M
e
×
R
e
/10
R
e
=
10
∴
(
v
e
)
p
=
10
×
(
v
e
)
e
=
10
×
11
=
110
km
/
s