A plane electromagnetic wave of frequency 500 MHz is travelling in vacuum along y-direction. At a particular point in space and time, B =8.0 × 10-8 hat z T. The value of electric field at this point is: (speed of light =3 × 108 ms -1 ) hat x , hat y , hat z are unit vectors along x , y and direction.

Question

A plane electromagnetic wave of frequency 500 MHz is travelling in vacuum along y-direction. At a particular point in space and time, B =8.0 × 10-8 hat z T. The value of electric field at this point is: (speed of light =3 × 108 ms -1 ) hat x , hat y , hat z are unit vectors along x , y and direction. (A) -24 hat x V / m (B) 2.6 hat x V / m (C) 24 hat x V / m (D) -2.6 hat y V / m

Tardigrade Admin · Accepted Answer

f =5 × 108 HZ EM wave is travelling towards + hatj B =8.0 × 10-8 hat z T E = B × C =(8 × 10-8 hat z ) ×(3 × 108 hat y ) =-24 hat x V/m

$- 24 \overset{x}{^} V / m$

$2.6 \overset{x}{^} V / m$

$24 \overset{x}{^} V / m$

$- 2.6 \overset{y}{^} V / m$

$f = 5 \times 1 0^{8} H Z$
EM wave is travelling towards $+ \hat{j}$
$B = 8.0 \times 1 0^{- 8} \overset{z}{^} T$
$E = B \times C = (8 \times 1 0^{- 8} \overset{z}{^}) \times (3 \times 1 0^{8} \overset{y}{^})$
$= - 24 \overset{x}{^} V / m$

Q. A plane electromagnetic wave of frequency 500MHz is travelling in vacuum along y-direction. At a particular point in space and time, B=8.0×10−8z^T. The value of electric field at this point is: (speed of light =3×108ms−1 ) x^,y^​,z^ are unit vectors along x,y and direction.

−24x^V/m

2.6x^V/m

24x^V/m

−2.6y^​V/m

f=5×108HZ EM wave is travelling towards +j^​ B=8.0×10−8z^T E=B×C=(8×10−8z^)×(3×108y^​) =−24x^V/m

$- 24 \overset{x}{^} V / m$

$2.6 \overset{x}{^} V / m$

$24 \overset{x}{^} V / m$

$- 2.6 \overset{y}{^} V / m$

$f = 5 \times 1 0^{8} H Z$
EM wave is travelling towards $+ \hat{j}$
$B = 8.0 \times 1 0^{- 8} \overset{z}{^} T$
$E = B \times C = (8 \times 1 0^{- 8} \overset{z}{^}) \times (3 \times 1 0^{8} \overset{y}{^})$
$= - 24 \overset{x}{^} V / m$