A piece of wire of resistance 4 ohm is bent through 180 at its mid point and the two halves are twisted together. Then the resistance is

Question

A piece of wire of resistance 4 ohm is bent through 180 at its mid point and the two halves are twisted together. Then the resistance is (A) 8 ohms (B) 1 ohm (C) 2 ohms (D) 5 ohms.

Tardigrade Admin · Accepted Answer

Length is halved. Area is doubled. Since R = (ρ l/A) . Therefore R will become ( (1/4) ) times.

Q. A piece of wire of resistance 4 ohm is bent through 180 at its mid point and the two halves are twisted together. Then the resistance is

8 ohms

1 ohm

2 ohms

5 ohms.

Length is halved. Area is doubled. Since $R = \frac{ρ l}{A}$ . Therefore R will become $(\frac{1}{4})$ times.

Q. A piece of wire of resistance 4 ohm is bent through 180 at its mid point and the two halves are twisted together. Then the resistance is

8 ohms

1 ohm

2 ohms

5 ohms.

Length is halved. Area is doubled. Since R=Aρl​ . Therefore R will become (41​) times.

Length is halved. Area is doubled. Since $R = \frac{ρ l}{A}$ . Therefore R will become $(\frac{1}{4})$ times.