A photon of wavelength 4400 mathringA is passing through vacuum. The effective mass and momentum of the photon are respectively

Question

A photon of wavelength 4400 mathringA is passing through vacuum. The effective mass and momentum of the photon are respectively (A) 5 × 10-36 kg , 1.5 × 10-27 kg - m / s (B) 5 × 10-35 kg , 1.5 × 10-26 kg - m / s (C) Zero, 1.5 × 10-26 kg - m / s (D) 5 × 10-36 kg , 1.67 × 10-43 kg - m / s

Tardigrade Admin · Accepted Answer

p=(h/λ)=(6.6 × 10-34/4400 × 10-10) =1.5 × 10-27 kg ⋅ m / s and mass m=(p/c) =(1.5 × 10-27/3 × 108) =5 × 10-36 kg

Q. A photon of wavelength $4400 \overset{˚}{A}$ is passing through vacuum. The effective mass and momentum of the photon are respectively

$5 \times 1 0^{- 36} k g, 1.5 \times 1 0^{- 27} k g - m / s$

$5 \times 1 0^{- 35} k g, 1.5 \times 1 0^{- 26} k g - m / s$

Zero, $1.5 \times 1 0^{- 26} k g - m / s$

$5 \times 1 0^{- 36} k g, 1.67 \times 1 0^{- 43} k g - m / s$

$p = \frac{h}{λ} = \frac{6.6 \times 1 0 ^{- 34}}{4400 \times 1 0 ^{- 10}}$
$= 1.5 \times 1 0^{- 27} k g \cdot m / s$
and mass $m = \frac{p}{c} = \frac{1.5 \times 1 0 ^{- 27}}{3 \times 1 0 ^{8}}$
$= 5 \times 1 0^{- 36} k g$

Q. A photon of wavelength 4400A˚ is passing through vacuum. The effective mass and momentum of the photon are respectively

5×10−36kg,1.5×10−27kg−m/s

5×10−35kg,1.5×10−26kg−m/s

Zero, 1.5×10−26kg−m/s

5×10−36kg,1.67×10−43kg−m/s