A person's eye level is 1.5 m. He stands in front of 0.3 m long plane mirror which is 0.8 m above the ground. The length (in cm ) of the image he sees of himself is ?

Question

A person's eye level is 1.5 m. He stands in front of 0.3 m long plane mirror which is 0.8 m above the ground. The length (in cm ) of the image he sees of himself is ? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/7408b1a58a1062b2c8e2e8036a824c75-.png" /> Here B C=E D-(E B+D C) (which is in the field of view) ⇒ 1.5-(0.8+0.1) ⇒ 0.6 m

Q. A person's eye level is $1.5 m$ . He stands in front of $0.3 m$ long plane mirror which is $0.8 m$ above the ground. The length (in $c m$ ) of the image he sees of himself is ?

Here $BC = E D - (EB + D C)$ (which is in the field of view)
$\Rightarrow 1.5 - (0.8 + 0.1)$
$\Rightarrow 0.6 m$

Q. A person's eye level is 1.5m. He stands in front of 0.3m long plane mirror which is 0.8m above the ground. The length (in cm ) of the image he sees of himself is ?

Here BC=ED−(EB+DC) (which is in the field of view) ⇒1.5−(0.8+0.1) ⇒0.6m

Q. A person's eye level is $1.5 m$ . He stands in front of $0.3 m$ long plane mirror which is $0.8 m$ above the ground. The length (in $c m$ ) of the image he sees of himself is ?

Here $BC = E D - (EB + D C)$ (which is in the field of view)
$\Rightarrow 1.5 - (0.8 + 0.1)$
$\Rightarrow 0.6 m$