A person is moving with a velocity of 10 ms -1 towards north. A car moving with a velocity of 20 ms -1 towards south crosses the person. The velocity of car relative to the person is

Question

A person is moving with a velocity of 10 ms -1 towards north. A car moving with a velocity of 20 ms -1 towards south crosses the person. The velocity of car relative to the person is (A) -30 ms -1 (B) +20 ms -1 (C) 10 ms -1 (D) -10 ms -1

Tardigrade Admin · Accepted Answer

Let south to north direction be positive. Velocity of car, vC=-20 ms -1 Velocity of person, vP=+10 ms -1 vC P =vC-vP =(-20)-(10) =-30 ms -1

Q. A person is moving with a velocity of $10 m s^{- 1}$ towards north. A car moving with a velocity of $20 m s^{- 1}$ towards south crosses the person. The velocity of car relative to the person is

$- 30 m s^{- 1}$

$+ 20 m s^{- 1}$

$10 m s^{- 1}$

$- 10 m s^{- 1}$

Let south to north direction be positive.
Velocity of car, $v_{C} = - 20 m s^{- 1}$
Velocity of person, $v_{P} = + 10 m s^{- 1}$
$v_{CP} = v_{C} - v_{P}$
$= (- 20) - (10)$
$= - 30 m s^{- 1}$

Q. A person is moving with a velocity of 10ms−1 towards north. A car moving with a velocity of 20ms−1 towards south crosses the person. The velocity of car relative to the person is

−30ms−1

+20ms−1

10ms−1

−10ms−1