A person adds 1.71 gram of sugar (C12H22O11) in order to sweeten his tea. The number of carbon atoms added are (mol. mass of sugar = 342)

Question

A person adds 1.71 gram of sugar (C12H22O11) in order to sweeten his tea. The number of carbon atoms added are (mol. mass of sugar = 342) (A) 3.6 × 1022 (B) 7.2 × 1021 (C) 0.05 (D) 6.6 × 1022

Tardigrade Admin · Accepted Answer

Moles of sugar added =(1.71/342)=5×10-3 Carbon atoms added =12×5×10-3×6.02×1023 =3.61×1022

Q. A person adds 1.71 gram of sugar $(C_{12} H_{22} O_{11})$ in order to sweeten his tea. The number of carbon atoms added are (mol. mass of sugar = 342)

$3.6 \times 1 0^{22}$

$7.2 \times 1 0^{21}$

0.05

$6.6 \times 1 0^{22}$

Moles of sugar added $= \frac{1.71}{342} = 5 \times 1 0^{- 3}$
Carbon atoms added
$= 12 \times 5 \times 1 0^{- 3} \times 6.02 \times 1 0^{23}$
$= 3.61 \times 1 0^{22}$

Q. A person adds 1.71 gram of sugar (C12​H22​O11​) in order to sweeten his tea. The number of carbon atoms added are (mol. mass of sugar = 342)

3.6×1022

7.2×1021