A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s-2 at a distance of 5 m from the mean position. The time period of oscillation is

Question

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s-2 at a distance of 5 m from the mean position. The time period of oscillation is (A) 1 s (B) 2 π s (C) 2s (D) π s

Tardigrade Admin · Accepted Answer

|a| = ω2y ⇒ 20 = ω2 (5) ⇒ ω = 2 (rad/s) T = (2 π/ω) = (2 π/2) = π s

Q. A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20 m / s^{- 2}$ at a distance of $5 m$ from the mean position. The time period of oscillation is

1 s

2 $π$ s

2s

$π s$

$∣ a ∣ = ω^{2} y$
$\Rightarrow 20 = ω^{2} (5)$
$\Rightarrow ω = 2 \frac{r a d}{s}$
$T = \frac{2 π}{ω} = \frac{2 π}{2} = π s$

Q. A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20m/s−2 at a distance of 5m from the mean position. The time period of oscillation is

1 s

2 π s

2s

πs

∣a∣=ω2y ⇒20=ω2(5) ⇒ω=2srad​ T=ω2π​=22π​=πs

Q. A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20 m / s^{- 2}$ at a distance of $5 m$ from the mean position. The time period of oscillation is

2 $π$ s

$π s$

$∣ a ∣ = ω^{2} y$
$\Rightarrow 20 = ω^{2} (5)$
$\Rightarrow ω = 2 \frac{r a d}{s}$
$T = \frac{2 π}{ω} = \frac{2 π}{2} = π s$