A particle travels in circle of radius 20 cm at a speed that uniformly increases. It speed changes from 5 m / s to 6 m / s in 2 s. The angular acceleration is

Question

A particle travels in circle of radius 20 cm at a speed that uniformly increases. It speed changes from 5 m / s to 6 m / s in 2 s. The angular acceleration is (A) 2 rad s -2 (B) 2.5 rad s -2 (C) 5 rad s -2 (D) 1.5 rad s -2

Tardigrade Admin · Accepted Answer

at=(d v/d t)=(v2-v1/t2-t1)=(6-5/2) =0.5 m s -2 α=(at/R)=(0.5/0.2) =2.5 rad s -2

Q. A particle travels in circle of radius $20 c m$ at a speed that uniformly increases. It speed changes from $5 m / s$ to $6 m / s$ in $2 s$ . The angular acceleration is

$2 r a d s^{- 2}$

$2.5 r a d s^{- 2}$

$5 r a d s^{- 2}$

$1.5 r a d s^{- 2}$

$a_{t} = \frac{d v}{d t} = \frac{v _{2} - v _{1}}{t _{2} - t _{1}} = \frac{6 - 5}{2}$
$= 0.5 m s^{- 2}$
$α = \frac{a _{t}}{R} = \frac{0.5}{0.2}$
$= 2.5 r a d s^{- 2}$

Q. A particle travels in circle of radius 20cm at a speed that uniformly increases. It speed changes from 5m/s to 6m/s in 2s. The angular acceleration is

2rads−2

2.5rads−2

5rads−2

1.5rads−2