A particle starts from rest at t=0 and moves in a straight line with an acceleration shown below. The velocity of the particle at t=3 s is:

Question

A particle starts from rest at t=0 and moves in a straight line with an acceleration shown below. The velocity of the particle at t=3 s is: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/fca971ecdbba84a9c0541933a8f160d9-.png" /> (A) 5 m / s 2 (B) 6 m / s 2 (C) 10 m / s 2 (D) 15 m / s 2

Tardigrade Admin · Accepted Answer

Velocity = area under acceleration time graph text Velocity =(5 × 1)-(5 × 1)+(5 × 1) text Velocity =5-5+5=5 m / s 2

Q. A particle starts from rest at $t = 0$ and moves in a straight line with an acceleration shown below. The velocity of the particle at $t = 3 s$ is:

$5 m / s^{2}$

$6 m / s^{2}$

$10 m / s^{2}$

$15 m / s^{2}$

Velocity $=$ area under acceleration time graph
$Velocity = (5 \times 1) - (5 \times 1) + (5 \times 1)$
$Velocity = 5 - 5 + 5 = 5 m / s^{2}$

Q. A particle starts from rest at t=0 and moves in a straight line with an acceleration shown below. The velocity of the particle at t=3s is:

5m/s2

6m/s2

10m/s2

15m/s2