A particle of mass m is performing vertical circular motion (see figure). If the average speed of the particle is increased, then at which point maximum breaking possibility of the string :-

Question

A particle of mass m is performing vertical circular motion (see figure). If the average speed of the particle is increased, then at which point maximum breaking possibility of the string :- <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-lvz21exxi1r31jvs.jpg" /> (A) A (B) B (C) C (D) D

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-lvz21exxi1r33pzm.jpg" /> At position B tension is maximum, so breaking possibility of string at this point is high. T=mg+(mv2/r)

Q. A particle of mass $m$ is performing vertical circular motion (see figure). If the average speed of the particle is increased, then at which point maximum breaking possibility of the string :-

$A$

$B$

$C$

$D$

At position $B$ tension is maximum, so breaking possibility of string at this point is high.
$T = m g + \frac{m v ^{2}}{r}$

Q. A particle of mass m is performing vertical circular motion (see figure). If the average speed of the particle is increased, then at which point maximum breaking possibility of the string :-

A

B

C

D

At position B tension is maximum, so breaking possibility of string at this point is high. T=mg+rmv2​

Q. A particle of mass $m$ is performing vertical circular motion (see figure). If the average speed of the particle is increased, then at which point maximum breaking possibility of the string :-

$A$

$B$

$C$

$D$

At position $B$ tension is maximum, so breaking possibility of string at this point is high.
$T = m g + \frac{m v ^{2}}{r}$