A particle of mass 500 gm is moving in a straight line with velocity v=b x5 / 2. The work done by the net force during its displacement from x=0 to x =4 m is: (. Take . b =0.25 m -3 / 2 s -1).

Question

A particle of mass 500 gm is moving in a straight line with velocity v=b x5 / 2. The work done by the net force during its displacement from x=0 to x =4 m is: (. Take . b =0.25 m -3 / 2 s -1). (A) 2 J (B) 4 J (C) 8 J (D) 16 J

Tardigrade Admin · Accepted Answer

By work energy theorem work done by net force =Δ K.E. ⇒ W =(1/2) mu f 2-(1/2) mu i 2 w =(1/2) × 0.5 ×(0.25)2 ×(4)5 w =16 J

Q. A particle of mass $500 g m$ is moving in a straight line with velocity $v = b x^{5/2}$ . The work done by the net force during its displacement from $x = 0$ to $x = 4 m$ is : $($ Take $b = 0.25 m^{- 3/2} s^{- 1})$ .

2 J

4 J

8 J

16 J

By work energy theorem
work done by net force $= Δ K$ .E.
$\Rightarrow W = \frac{1}{2} m u_{f}^{2} - \frac{1}{2} m u_{i}^{2}$
$w = \frac{1}{2} \times 0.5 \times (0.25)^{2} \times (4)^{5}$
$w = 16 J$

Q. A particle of mass 500gm is moving in a straight line with velocity v=bx5/2. The work done by the net force during its displacement from x=0 to x=4m is : ( Take b=0.25m−3/2s−1).

2 J

4 J

8 J

16 J

By work energy theorem work done by net force =ΔK.E. ⇒W=21​muf2​−21​mui2​ w=21​×0.5×(0.25)2×(4)5 w=16J

Q. A particle of mass $500 g m$ is moving in a straight line with velocity $v = b x^{5/2}$ . The work done by the net force during its displacement from $x = 0$ to $x = 4 m$ is : $($ Take $b = 0.25 m^{- 3/2} s^{- 1})$ .

By work energy theorem
work done by net force $= Δ K$ .E.
$\Rightarrow W = \frac{1}{2} m u_{f}^{2} - \frac{1}{2} m u_{i}^{2}$
$w = \frac{1}{2} \times 0.5 \times (0.25)^{2} \times (4)^{5}$
$w = 16 J$