A particle moving with uniform acceleration has velocity of 6 m s -1 at a distance 5 m from the initial position. After moving another 7 m the velocity becomes 8 m s -1. The initial velocity and acceleration of the particle are

Question

A particle moving with uniform acceleration has velocity of 6 m s -1 at a distance 5 m from the initial position. After moving another 7 m the velocity becomes 8 m s -1. The initial velocity and acceleration of the particle are (A) 2 m s -1 ; 4 m s -2 (B) 4 m s -1 ; 2 m s -2 (C) 4 m s -1 ; 4 m s -2 (D) 6 m s -1 ; 1 m s -2

Tardigrade Admin · Accepted Answer

Using, v2=u2+2 a s, For second part of motion, we have (8)2=(6)2+2 × a × 7 or a=2 m s -2 For first part of motion, (6)2=u2+2 × 2 × 5 or u=4 m s -1

Q. A particle moving with uniform acceleration has velocity of $6 m s^{- 1}$ at a distance 5 m from the initial position. After moving another 7 m the velocity becomes $8 m s^{- 1}$ . The initial velocity and acceleration of the particle are

$2 m s^{- 1}; 4 m s^{- 2}$

$4 m s^{- 1}; 2 m s^{- 2}$

$4 m s^{- 1}; 4 m s^{- 2}$

$6 m s^{- 1}; 1 m s^{- 2}$

Using, $v^{2} = u^{2} + 2 a s$ ,
For second part of motion, we have
$(8)^{2} = (6)^{2} + 2 \times a \times 7$ or $a = 2 m s^{- 2}$
For first part of motion,
$(6)^{2} = u^{2} + 2 \times 2 \times 5$ or $u = 4 m s^{- 1}$

Q. A particle moving with uniform acceleration has velocity of 6ms−1 at a distance 5 m from the initial position. After moving another 7 m the velocity becomes 8ms−1. The initial velocity and acceleration of the particle are

2ms−1;4ms−2

4ms−1;2ms−2

4ms−1;4ms−2

6ms−1;1ms−2