A particle is revolving in a circular path of radius 25 m with constant angular speed 12 rev / min. Then the angular acceleration of particle is

Question

A particle is revolving in a circular path of radius 25 m with constant angular speed 12 rev / min. Then the angular acceleration of particle is (A) 2 π2 rad / s 2 (B) 4 π2 rad / s 2 (C) π2 rad / s 2 (D) Zero

Tardigrade Admin · Accepted Answer

Angular acceleration is the rate of change of angular speed or angular velocity if vecω remains constant then α=0

Q. A particle is revolving in a circular path of radius $25 m$ with constant angular speed $12 re v / min$ . Then the angular acceleration of particle is

$2 π^{2} r a d / s^{2}$

$4 π^{2} r a d / s^{2}$

$π^{2} r a d / s^{2}$

Zero

Angular acceleration is the rate of change of angular speed or angular velocity if $ω$ remains constant then $α = 0$

Q. A particle is revolving in a circular path of radius 25m with constant angular speed 12rev/min. Then the angular acceleration of particle is

2π2rad/s2

4π2rad/s2

π2rad/s2