A particle is projected horizontally with a speed u from the top of a plane inclined at an angle θ with the horizontal. How far from the point of projection will the particle strike the plane?

Question

A particle is projected horizontally with a speed u from the top of a plane inclined at an angle θ with the horizontal. How far from the point of projection will the particle strike the plane? (A) 2 u2 tan θ ⋅ sec θ / g (B) u2 sin θ ⋅ cos θ / g (C) 3 u2 cos θ ⋅ sec θ / g (D) 2 u2 sin 2 θ / g

Tardigrade Admin · Accepted Answer

Correct answer is (a) 2 u2 tan θ ⋅ sec θ / g

Q. A particle is projected horizontally with a speed $u$ from the top of a plane inclined at an angle $θ$ with the horizontal. How far from the point of projection will the particle strike the plane?

$2 u^{2} tan θ \cdot sec θ / g$

$u^{2} sin θ \cdot cos θ / g$

$3 u^{2} cos θ \cdot sec θ / g$

$2 u^{2} sin^{2} θ / g$

Correct answer is (a) $2 u^{2} tan θ \cdot sec θ / g$

Q. A particle is projected horizontally with a speed u from the top of a plane inclined at an angle θ with the horizontal. How far from the point of projection will the particle strike the plane?

2u2tanθ⋅secθ/g

u2sinθ⋅cosθ/g

3u2cosθ⋅secθ/g

2u2sin2θ/g