A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angle 30? and 60? from vertical (lowest position) are T1 and T2 respectively, then

Question

A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angle 30? and 60? from vertical (lowest position) are T1 and T2 respectively, then (A)  T1=T2  (B)  T2>T1  (C)  T1>T2  (D) tension in the string always remains the same

Tardigrade Admin · Accepted Answer

Tension in the string T=(mv2/r)+mg cos θ For θ =30o,T1=(mv2/r)+mg cos 30o For θ =60o,T2=(mv2/r)+mg cos 60o ∴ T1>T2.

Q. A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angle 30? and 60? from vertical (lowest position) are $T_{1}$ and $T_{2}$ respectively, then

$T_{1} = T_{2}$

$T_{2} > T_{1}$

$T_{1} > T_{2}$

tension in the string always remains the same

Tension in the string $T = \frac{m v ^{2}}{r} + m g cos θ$ For $θ = 30^{o}, T_{1} = \frac{m v ^{2}}{r} + m g cos 30^{o}$ For $θ = 60^{o}, T_{2} = \frac{m v ^{2}}{r} + m g cos 60^{o}$ $∴$ $T_{1} > T_{2} .$

Q. A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angle 30? and 60? from vertical (lowest position) are T1​ and T2​ respectively, then

T1​=T2​

T2​>T1​

T1​>T2​