A particle is moving along a circular path of radius 5 m with a uniform speed 5 ms - 1 What will be the average acceleration when the particle completes half revolution ?

Question

A particle is moving along a circular path of radius 5 m with a uniform speed 5 ms - 1 What will be the average acceleration when the particle completes half revolution ? (A) Zero (B) 10 ms - 2  (C) 10 π ms - 2  (D)  ( 10 / π ) ms - 2

Tardigrade Admin · Accepted Answer

When the particle completes half revolution, change in velocity

△ v = [5 - (- 5)] m s^{- 1} = 10 m s^{- 1}

Time taken to complete the half revolution is

t = \frac{π r}{v} = \frac{π \times 5}{5} = π

second
Thus, average acceleration

a_{v} = \frac{Δ v}{t} = \frac{10}{π} m s^{- 2}

Q. A particle is moving along a circular path of radius $5 m$ with a uniform speed $5 m s^{- 1}$ What will be the average acceleration when the particle completes half revolution ?

Zero

$10 m s^{- 2}$

$10 π m s^{- 2}$

$\frac{10}{π} m s^{- 2}$

When the particle completes half revolution, change in velocity
$△ v = [5 - (- 5)] m s^{- 1} = 10 m s^{- 1}$
Time taken to complete the half revolution is
$t = \frac{π r}{v} = \frac{π \times 5}{5} = π$ second
Thus, average acceleration
$a_{v} = \frac{Δ v}{t} = \frac{10}{π} m s^{- 2}$

Q. A particle is moving along a circular path of radius 5m with a uniform speed 5ms−1 What will be the average acceleration when the particle completes half revolution ?

Zero

10ms−2

10πms−2

π10​ms−2

When the particle completes half revolution, change in velocity △v=[5−(−5)]ms−1=10ms−1 Time taken to complete the half revolution is t=vπr​=5π×5​=π second Thus, average acceleration av​=tΔv​=π10​ms−2

Q. A particle is moving along a circular path of radius $5 m$ with a uniform speed $5 m s^{- 1}$ What will be the average acceleration when the particle completes half revolution ?

$10 m s^{- 2}$

$10 π m s^{- 2}$

$\frac{10}{π} m s^{- 2}$

When the particle completes half revolution, change in velocity
$△ v = [5 - (- 5)] m s^{- 1} = 10 m s^{- 1}$
Time taken to complete the half revolution is
$t = \frac{π r}{v} = \frac{π \times 5}{5} = π$ second
Thus, average acceleration
$a_{v} = \frac{Δ v}{t} = \frac{10}{π} m s^{- 2}$