A particle executes the simple harmonic motion with an amplitude 'A'. The distance travelled by it in one periodic time is

Question

A particle executes the simple harmonic motion with an amplitude 'A'. The distance travelled by it in one periodic time is (A) (A/2) (B) A (C) 2A (D) 4A

Tardigrade Admin · Accepted Answer

Key Idea One time period means the total time in which the particle returns to the same point and in the same direction from where it was released.
Now, in simple harmonic motion (SHM) total distance travelled is

4 A

.

This is because the particle covers

A

in

\frac{T}{4}

time period i.e., when it moves from

A

to

B

, So in complete

T

time it covers 4 times the amplitude distance i.e.,

4 A

Q. A particle executes the simple harmonic motion with an amplitude $^{'} A^{'}$ . The distance travelled by it in one periodic time is

$\frac{A}{2}$

$A$

$2 A$

$4 A$

Q. A particle executes the simple harmonic motion with an amplitude ′A′. The distance travelled by it in one periodic time is

2A​

A

2A

4A

Q. A particle executes the simple harmonic motion with an amplitude $^{'} A^{'}$ . The distance travelled by it in one periodic time is

$\frac{A}{2}$

$A$

$2 A$

$4 A$