A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 × 10-6 J/T when a magnetic intensity of 60 × 103 A/m is applied. Its magnetic susceptibility is :

Question

A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 × 10-6 J/T when a magnetic intensity of 60 × 103 A/m is applied. Its magnetic susceptibility is : (A) 2.3 × 10-2 (B) 3.3 × 10-2 (C) 3.3 × 10-4 (D) 4.3 × 10-2

Tardigrade Admin · Accepted Answer

chi = (I/H) I = ( textMagnetic textmoment/ textVolume) I = (20 ×10-6/10-6) = 20 N /m2 chi = (20/60 ×10+3) = (1/3) ×10-3 = 0.33 ×10-3 = 3.3 ×10-4

Q. A paramagnetic substance in the form of a cube with sides $1 c m$ has a magnetic dipole moment of $20 \times 1 0^{- 6} J / T$ when a magnetic intensity of $60 \times 1 0^{3} A / m$ is applied. Its magnetic susceptibility is :

$2.3 \times 1 0^{- 2}$

$3.3 \times 1 0^{- 2}$

$3.3 \times 1 0^{- 4}$

$4.3 \times 1 0^{- 2}$

$χ = \frac{I}{H}$
$I = \frac{Magnetic moment}{Volume}$
$I = \frac{20 \times 1 0 ^{- 6}}{1 0 ^{- 6}} = 20 N / m^{2}$
$χ = \frac{20}{60 \times 1 0 ^{+ 3}} = \frac{1}{3} \times 1 0^{- 3}$
$= 0.33 \times 1 0^{- 3} = 3.3 \times 1 0^{- 4}$

Q. A paramagnetic substance in the form of a cube with sides 1cm has a magnetic dipole moment of 20×10−6J/T when a magnetic intensity of 60×103A/m is applied. Its magnetic susceptibility is :

2.3×10−2

3.3×10−2

3.3×10−4

4.3×10−2