A parallel-plate capacitor has circular plates of radius 8 cm and plate separation 1 mm. What will be the charge on the plates if a potential difference of 100 V is applied?

Question

A parallel-plate capacitor has circular plates of radius 8 cm and plate separation 1 mm. What will be the charge on the plates if a potential difference of 100 V is applied? (A) 1.78 × 10-8 C (B) 1.78 × 10-5 C (C) 4.3 × 104 C (D) 2 × 10-9 C

Tardigrade Admin · Accepted Answer

C=(ε0 A/d) =(8.85 × 10-12 × 3.14 × 0.08 × 0.08/1 × 10-3) q=C V =(8.85 × 10-12 × 3.14 × .08 × .08 × 100 V /1 × 10-3) =1.78 × 10-8 C

Q. A parallel-plate capacitor has circular plates of radius $8 c m$ and plate separation $1 mm$ . What will be the charge on the plates if a potential difference of $100 V$ is applied?

$1.78 \times 1 0^{- 8} C$

$1.78 \times 1 0^{- 5} C$

$4.3 \times 1 0^{4} C$

$2 \times 1 0^{- 9} C$

$C = \frac{ε _{0} A}{d} = \frac{8.85 \times 1 0 ^{- 12} \times 3.14 \times 0.08 \times 0.08}{1 \times 1 0 ^{- 3}}$
$q = C V = \frac{8.85 \times 1 0 ^{- 12} \times 3.14 \times .08 \times .08 \times 100 V}{1 \times 1 0 ^{- 3}}$
$= 1.78 \times 1 0^{- 8} C$

Q. A parallel-plate capacitor has circular plates of radius 8cm and plate separation 1mm. What will be the charge on the plates if a potential difference of 100V is applied?

1.78×10−8C

1.78×10−5C

4.3×104C

2×10−9C