A parallel beam of light is incident on the surface of a transparent hemisphere of radius R and refractive index 2.0 as shown in figure. The position of the image formed by refraction at the first surface is:

Question

A parallel beam of light is incident on the surface of a transparent hemisphere of radius R and refractive index 2.0 as shown in figure. The position of the image formed by refraction at the first surface is: (A) R /2 (B) R (C) 2R (D) 3R

Tardigrade Admin · Accepted Answer

Using, (μ/ v )-(1/ u )=(μ-1/ R ) or (2/ v )-(1/∞)=(2-1/ R ) v =2 R

Q. A parallel beam of light is incident on the surface of a transparent hemisphere of radius $R$ and refractive index $2.0$ as shown in figure. The position of the image formed by refraction at the first surface is:

R /2

R

2R

3R

Using, $\frac{μ}{v} - \frac{1}{u} = \frac{μ - 1}{R}$
or $\frac{2}{v} - \frac{1}{\infty} = \frac{2 - 1}{R}$
$v = 2 R$

Q. A parallel beam of light is incident on the surface of a transparent hemisphere of radius R and refractive index 2.0 as shown in figure. The position of the image formed by refraction at the first surface is:

R /2

R

2R

3R

Using, vμ​−u1​=Rμ−1​ or v2​−∞1​=R2−1​ v=2R

Q. A parallel beam of light is incident on the surface of a transparent hemisphere of radius $R$ and refractive index $2.0$ as shown in figure. The position of the image formed by refraction at the first surface is:

Using, $\frac{μ}{v} - \frac{1}{u} = \frac{μ - 1}{R}$
or $\frac{2}{v} - \frac{1}{\infty} = \frac{2 - 1}{R}$
$v = 2 R$