A nuclide of an alkaline earth metal undergoes radioactive decay by emission of three α-particles in succession. The group of the periodic table to which the resulting daughter element would belong is

Question

A nuclide of an alkaline earth metal undergoes radioactive decay by emission of three α-particles in succession. The group of the periodic table to which the resulting daughter element would belong is (A) group 14 (B) group 16 (C) group 4 (D) group 6

Tardigrade Admin · Accepted Answer

After radioactive decay of element by three successive emission of α-particles, the last element (stable) Pb is obtained which belongs to group 14 of periodic table.

Q. A nuclide of an alkaline earth metal undergoes radioactive decay by emission of three $α$ -particles in succession. The group of the periodic table to which the resulting daughter element would belong is

group 14

group 16

group 4

group 6

After radioactive decay of element by three successive emission of $α$ -particles, the last element (stable) Pb is obtained which belongs to group 14 of periodic table.

Q. A nuclide of an alkaline earth metal undergoes radioactive decay by emission of three α-particles in succession. The group of the periodic table to which the resulting daughter element would belong is