A network of resistances, cell and capacitor C( = 2 μ F) is shown in adjoining figure. In steady state condition, the charge on 2 μ F capacitor is Q, while R is unknown resistance. Values of Q and R are respectively

Question

A network of resistances, cell and capacitor C( = 2 μ F) is shown in adjoining figure. In steady state condition, the charge on 2 μ F capacitor is Q, while R is unknown resistance. Values of Q and R are respectively (A) 4 μ C and 10 Ω (B) 4 μ C and 4 Ω (C) 2 μ C and 2 Ω (D) 8 μ C and 4 Ω

Tardigrade Admin · Accepted Answer

In the steady state, no current will flow through capacitor.
Using Kirchhof's voltage law to the circuit

A C D

we have,

10 - 2 + 1 \times R + 1 \times 2 = 0

or

R = 10 Ω

Potential diffrence across

C

and

D

V_{C} - V_{D} = 2 \times 1 = 2 V

As

V_{D} = 0 V

So,

V_{C} = 2 V

Potential difference across capacitor

= 4 - 2 = 2 V

∴

Charge on capacitor

Q = C V = 2 μ F \times 2 = 4 μ C

Q. A network of resistances, cell and capacitor $C (= 2 μ F)$ is shown in adjoining figure. In steady state condition, the charge on $2 μ F$ capacitor is $Q$ , while $R$ is unknown resistance. Values of $Q$ and $R$ are respectively

$4 μ C$ and $10 Ω$

$4 μ C$ and $4 Ω$

$2 μ C$ and $2 Ω$

$8 μ C$ and $4 Ω$

Q. A network of resistances, cell and capacitor C(=2μF) is shown in adjoining figure. In steady state condition, the charge on 2μFcapacitor is Q, while R is unknown resistance. Values of Q and R are respectively

4μC and 10Ω

4μC and 4Ω

2μC and 2Ω

8μC and 4Ω

Q. A network of resistances, cell and capacitor $C (= 2 μ F)$ is shown in adjoining figure. In steady state condition, the charge on $2 μ F$ capacitor is $Q$ , while $R$ is unknown resistance. Values of $Q$ and $R$ are respectively

$4 μ C$ and $10 Ω$

$4 μ C$ and $4 Ω$

$2 μ C$ and $2 Ω$

$8 μ C$ and $4 Ω$