A n-p-n transistor is connected in common emitter configuration (see figure) in which collector voltage drop across load resistance (800 Ω ) connected to the collector circuit is 0.8 V. The collector current is:

Question

A n-p-n transistor is connected in common emitter configuration (see figure) in which collector voltage drop across load resistance (800 Ω ) connected to the collector circuit is 0.8 V. The collector current is: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5f7b3365c48ded7a0f3956dc26b29478-.png" /> (A) 2 mA (B) 0.1 mA (C) 1 mA (D) 0.2 mA

Tardigrade Admin · Accepted Answer

Voltage drop across load resistance = 0.8 V IC=(Vc/Rc)=(0.8/800) =10-3A =1 mA

Q. A n-p-n transistor is connected in common emitter configuration (see figure) in which collector voltage drop across load resistance $(800 Ω)$ connected to the collector circuit is $0.8 V$ . The collector current is :

$2 m A$

$0.1 m A$

$1 m A$

$0.2 m A$

Voltage drop across load resistance $= 0.8 V$
$I_{C} = \frac{V _{c}}{R _{c}} = \frac{0.8}{800}$
$= 1 0^{- 3} A$
$= 1 m A$

Q. A n-p-n transistor is connected in common emitter configuration (see figure) in which collector voltage drop across load resistance (800Ω) connected to the collector circuit is 0.8V. The collector current is :

2mA

0.1mA

1mA

0.2mA