A moving coil Galvanometer of resistance 100 Ω is used as an ammeter using aresistance 0.1 Ω. The maximum deflection current in the Galvanometer is 100 μ A. Find the minimum current in the circuit so that ammeter shows maximum deflection?

Question

A moving coil Galvanometer of resistance 100 Ω is used as an ammeter using aresistance 0.1 Ω. The maximum deflection current in the Galvanometer is 100 μ A. Find the minimum current in the circuit so that ammeter shows maximum deflection? (A) 100.1 mA (B) 1000. 1 mA (C) 10.01 mA (D) 1.01 mA

Tardigrade Admin · Accepted Answer

We are given with following ammeter <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/004fd62e216360d502885a3ac11e7eda-.png" /> Now, VA B=Ig G=(I-Ig) S (100 × 10-6) 100=(I-100 × 10-6) 0.1 I-100 × 10-6=10-1 I=0.1+100 × 10-6 =0.1+0.0001=0.1001 A=100.1 mA So, circuit current is 100.1 mA.

Q. A moving coil Galvanometer of resistance $100 Ω$ is used as an ammeter using aresistance $0.1 Ω$ . The maximum deflection current in the Galvanometer is $100 μ A$ . Find the minimum current in the circuit so that ammeter shows maximum deflection?

$100.1 m A$

1000. 1{\,} mA$

$10.01 m A$

$1.01 m A$

We are given with following ammeter

Now, $V_{A B} = I_{g} G = (I - I_{g}) S$
$(100 \times 1 0^{- 6}) 100 = (I - 100 \times 1 0^{- 6}) 0.1$
$I - 100 \times 1 0^{- 6} = 1 0^{- 1}$
$I = 0.1 + 100 \times 1 0^{- 6}$
$= 0.1 + 0.0001 = 0.1001 A = 100.1 m A$
So, circuit current is $100.1 m A$ .

Q. A moving coil Galvanometer of resistance 100Ω is used as an ammeter using aresistance 0.1Ω. The maximum deflection current in the Galvanometer is 100μA. Find the minimum current in the circuit so that ammeter shows maximum deflection?

100.1mA

1000. 1{\,} mA$

10.01mA

1.01mA

We are given with following ammeter Now, VAB​=Ig​G=(I−Ig​)S (100×10−6)100=(I−100×10−6)0.1 I−100×10−6=10−1 I=0.1+100×10−6 =0.1+0.0001=0.1001A=100.1mA So, circuit current is 100.1mA.

Q. A moving coil Galvanometer of resistance $100 Ω$ is used as an ammeter using aresistance $0.1 Ω$ . The maximum deflection current in the Galvanometer is $100 μ A$ . Find the minimum current in the circuit so that ammeter shows maximum deflection?

$100.1 m A$

$10.01 m A$

$1.01 m A$

We are given with following ammeter

Now, $V_{A B} = I_{g} G = (I - I_{g}) S$
$(100 \times 1 0^{- 6}) 100 = (I - 100 \times 1 0^{- 6}) 0.1$
$I - 100 \times 1 0^{- 6} = 1 0^{- 1}$
$I = 0.1 + 100 \times 1 0^{- 6}$
$= 0.1 + 0.0001 = 0.1001 A = 100.1 m A$
So, circuit current is $100.1 m A$ .