A mixture of 4g of hydrogen and 8g of helium at NTP has a density about

Question

A mixture of 4g of hydrogen and 8g of helium at NTP has a density about (A) 0.22kgm- 3 (B) 0.62kgm- 3 (C) 1.12kgm- 3 (D) 0.13kgm- 3

Tardigrade Admin · Accepted Answer

4g H2 means 2g -moles and 8g He means 2g -moles. Now M=(n1 M1 + n2 M2/n1 + n2)=((2) (2) + (2) (4)/2 + 2) =3gmol- 1 ρ =(P M/R T)=((1 . 013 × (10)5) (3 × (10)- 3)/(8 . 31) (273)) =0.13kgm- 3

Q. A mixture of $4 g$ of hydrogen and $8 g$ of helium at $NTP$ has a density about

$0.22 k g m^{- 3}$

$0.62 k g m^{- 3}$

$1.12 k g m^{- 3}$

$0.13 k g m^{- 3}$

Q. A mixture of 4g of hydrogen and 8g of helium at NTP has a density about

0.22kgm−3

0.62kgm−3

1.12kgm−3

0.13kgm−3

4g H2​ means 2g -moles and 8g He means 2g -moles. Now M=n1​+n2​n1​M1​+n2​M2​​=2+2(2)(2)+(2)(4)​ =3gmol−1 ρ=RTPM​=(8.31)(273)(1.013×(10)5)(3×(10)−3)​ =0.13kgm−3

Q. A mixture of $4 g$ of hydrogen and $8 g$ of helium at $NTP$ has a density about

$0.22 k g m^{- 3}$

$0.62 k g m^{- 3}$

$1.12 k g m^{- 3}$

$0.13 k g m^{- 3}$