A mixture of 2 moles of helium gas (atomic mass = 4u), and 1 mole of argon gas (atomic mass = 40 u) is kept at 300 K in a container. The ratio of their rms speeds [(Vrms( texthelium)/Vrms (( textargon))] is close to :

Question

A mixture of 2 moles of helium gas (atomic mass = 4u), and 1 mole of argon gas (atomic mass = 40 u) is kept at 300 K in a container. The ratio of their rms speeds [(Vrms( texthelium)/Vrms (( textargon))] is close to : (A) 2.24 (B) 0.45 (C) 0.32 (D) 3.16

Tardigrade Admin · Accepted Answer

(Vrms (He)/Vrms(Ar)) = √(MAr/MHe) = √(40/4) = 3.16

Q. A mixture of $2$ moles of helium gas (atomic mass = $4 u$ ), and $1$ mole of argon gas (atomic mass = $40 u$ ) is kept at $300 K$ in a container. The ratio of their rms speeds $[\frac{V _{r m s} ( helium )}{V _{r m s} (( argon )}]$ is close to :

2.24

0.45

0.32

3.16

$\frac{V _{r m s} ( He )}{V _{r m s} ( A r )} = \frac{M _{A r}}{M _{He}} = \frac{40}{4} = 3.16$

Q. A mixture of 2 moles of helium gas (atomic mass = 4u), and 1 mole of argon gas (atomic mass = 40u) is kept at 300K in a container. The ratio of their rms speeds [Vrms​((argon)Vrms​(helium)​]is close to :