A mercury drop of radius 1 cm is sprayed into 106 drops of equal size. The energy expended in joule is (surface tension of mercury is 460 × 10-3 N / m ):

Question

A mercury drop of radius 1 cm is sprayed into 106 drops of equal size. The energy expended in joule is (surface tension of mercury is 460 × 10-3 N / m ): (A) 0.057 (B) 5.7 (C) 5.7 × 10-4 (D) 5.7 × 10-6

Tardigrade Admin · Accepted Answer

R =1 cm , n =106 Δ bigcup=4 π R 2( n 1 / 3-1) T =4 π × 10-4(102-1) 460 × 10-3 =0.057 J

Q. A mercury drop of radius $1 c m$ is sprayed into $1 0^{6}$ drops of equal size. The energy expended in joule is (surface tension of mercury is $460 \times 1 0^{- 3} N / m$ ):

$0.057$

$5.7$

$5.7 \times 1 0^{- 4}$

$5.7 \times 1 0^{- 6}$

$R = 1 c m, n = 1 0^{6}$
$Δ ⋃ = 4 π R^{2} (n^{1/3} - 1) T$
$= 4 π \times 1 0^{- 4} (1 0^{2} - 1) 460 \times 1 0^{- 3}$
$= 0.057 J$

Q. A mercury drop of radius 1cm is sprayed into 106 drops of equal size. The energy expended in joule is (surface tension of mercury is 460×10−3N/m ):

0.057

5.7

5.7×10−4

5.7×10−6