A massless string going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given

Question

A massless string going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-lttwalqos8wiwxo4.jpg" /> (A) √2 textMg (B) √2 textmg (C) g√( textM + textm)2 + ( textm)2 (D) g√( textM + textm)2 + ( textM)2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-lttwalqos8wizizz.jpg" /> textR = √( textM)2 ( textg)2 + ( textm + textM)2 ( textg)2 ⇒ text R = √( textM)2 + ( textm + textM)2 text g

Q. A massless string going over a clamped pulley of mass $m$ supports a block of mass $M$ as shown in the figure. The force on the pulley by the clamp is given

$2 Mg$

$2 mg$

$g (M + m)^{2} + (m)^{2}$

$g (M + m)^{2} + (M)^{2}$

$R = (M)^{2} (g)^{2} + (m + M)^{2} (g)^{2} \Rightarrow R = (M)^{2} + (m + M)^{2} g$

Q. A massless string going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given

2​Mg

2​mg

g(M+m)2+(m)2​

g(M+m)2+(M)2​