A mass of an ideal gas undergoes a reversible isothermal compression. Its molecules will then have compared with initial state, the same (i) root mean square velocity (ii) mean momentum (iii) mean kinetic energy

Question

A mass of an ideal gas undergoes a reversible isothermal compression. Its molecules will then have compared with initial state, the same (i) root mean square velocity (ii) mean momentum (iii) mean kinetic energy (A) If (i), (ii), (iii) correct (B) If (i), (ii) correct (C) If (ii), (iii) correct (D) If (i) correct

Tardigrade Admin · Accepted Answer

Isothermal compression ⇒ T= constant v rms =√(3 R T/M) Mean momentum =m barv=m ⋅ √(8 R T/π M) Mean kinetic energy =(3/2) R T All the above are functions of temperature, which is a constant.

Q. A mass of an ideal gas undergoes a reversible isothermal compression. Its molecules will then have compared with initial state, the same
(i) root mean square velocity
(ii) mean momentum
(iii) mean kinetic energy

If (i), (ii), (iii) correct

If (i), (ii) correct

If (ii), (iii) correct

If (i) correct

Isothermal compression $\Rightarrow T =$ constant
$v_{r m s} = \frac{3 RT}{M}$
Mean momentum $= m \overset{v}{ˉ} = m \cdot \frac{8 RT}{π M}$
Mean kinetic energy $= \frac{3}{2} RT$
All the above are functions of temperature, which is a constant.

Q. A mass of an ideal gas undergoes a reversible isothermal compression. Its molecules will then have compared with initial state, the same (i) root mean square velocity (ii) mean momentum (iii) mean kinetic energy