A mass of 1 kg is suspended by means of a thread. The system is (i) lifted up with an acceleration of 4.9 m s-2 (ii) lowered with an acceleration of 4.9 m s-2 . The ratio of tension in the first and second case is

Question

A mass of 1 kg is suspended by means of a thread. The system is (i) lifted up with an acceleration of 4.9 m s-2 (ii) lowered with an acceleration of 4.9 m s-2 . The ratio of tension in the first and second case is (A) 3:1 (B) 1:2 (C) 1:3 (D) 2:1

Tardigrade Admin · Accepted Answer

Upward acceleration, m a=T1-m g T1=m(g+a) Downward acceleration, m a=m g-T2 or, T2=m(g-a) (T1/T2)=(g+a/g-a)=(9.8+4.9/9.8-4.9)=3: 1 text .

Q. A mass of $1 k g$ is suspended by means of a thread. The system is
(i) lifted up with an acceleration of $4.9 m$ $s^{- 2}$
(ii) lowered with an acceleration of $4.9 m$ $s^{- 2}$ .
The ratio of tension in the first and second case is

$3 : 1$

$1 : 2$

$1 : 3$

$2 : 1$

Upward acceleration, $ma = T_{1} - m g$
$T_{1} = m (g + a)$
Downward acceleration, $ma = m g - T_{2}$
or, $T_{2} = m (g - a)$
$\frac{T _{1}}{T _{2}} = \frac{g + a}{g - a} = \frac{9.8 + 4.9}{9.8 - 4.9} = 3 : 1 .$

Q. A mass of 1kg is suspended by means of a thread. The system is (i) lifted up with an acceleration of 4.9m s−2 (ii) lowered with an acceleration of 4.9m s−2 . The ratio of tension in the first and second case is

3:1

1:2

1:3

2:1