A mass m slip along the wall of a semi spherical surface of radius R . The velocity at the bottom of the surface is

Question

A mass m slip along the wall of a semi spherical surface of radius R . The velocity at the bottom of the surface is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/038168442256e14e3d194983edcea62c-.png" /> (A) √ operatornameRg (B) √2 R g (C) 2 √λ R g (D) √λ R g

Tardigrade Admin · Accepted Answer

According to the law of conservation of energy (1/2) m v2=mgR v=√2gR

Q. A mass m slip along the wall of a semi spherical surface of radius $R$ . The velocity at the bottom of the surface is

$Rg$

$2 R g$

$2 λ R g$

$λ R g$

According to the law of conservation of energy
$\frac{1}{2} m v^{2} = m g R$
$v = 2 g R$

Q. A mass m slip along the wall of a semi spherical surface of radius R . The velocity at the bottom of the surface is

Rg​

2Rg​

2λRg​

λRg​