Question

A man is standing on an international space station, which is orbiting earth at an altitude $520km$ with a constant speed $7.6km{s}^{-1}$ . If the mans weight is $50kg$, his acceleration is

• A. $7.6km{s}^{-2}$
• B. $7.6km{s}^{-2}$
• C. $8.4km{s}^{-2}$
• D. $10km{s}^{-2}$

Answer 1

Answer: (C)

A man of mass $50kg$ is standing on an international space station.
Then, distance of station from centre of earth
$r=R+h=6400+520$
$[\because$ radius of earth $R=6400km]$
$=6920km$
Now, centripetal acceleration $a=\frac{v^2}{r}$
$=\frac{{\left(7.6\times 10^3\right)}^2}{6920\times 10^3}=8.4m{s}^{-2}$