A magnetic field of 2× 10-2T acts at right angles to a coil of area 100 cm2, with 50 turns. The average e.m.f. induced in the coil is 0.1 V, when it is removed from the field in t sec. The value of t is

Question

A magnetic field of 2× 10-2T acts at right angles to a coil of area 100 cm2, with 50 turns. The average e.m.f. induced in the coil is 0.1 V, when it is removed from the field in t sec. The value of t is (A) 10 s (B) 0.1 s (C) 0.01 s (D) 1 s

Tardigrade Admin · Accepted Answer

∈=(-(φ2-φ1)/t)=(-(0-NBA)/t)=(NBA/t) t=(NBA/∈)=(50×2×10-2×10-2/0.1)=0.1 s

Q. A magnetic field of $2 \times 1 0^{- 2}$ T acts at right angles to a coil of area 100 $c m^{2}$ , with 50 turns. The average e.m.f. induced in the coil is 0.1 V, when it is removed from the field in t sec. The value of t is

10 s

0.1 s

0.01 s

1 s

$\in= \frac{- ( ϕ _{2} - ϕ _{1} )}{t} = \frac{- ( 0 - NB A )}{t} = \frac{NB A}{t}$
$t = \frac{NB A}{\in} = \frac{50 \times 2 \times 1 0 ^{- 2} \times 1 0 ^{- 2}}{0.1} = 0.1 s$

Q. A magnetic field of 2×10−2T acts at right angles to a coil of area 100 cm2, with 50 turns. The average e.m.f. induced in the coil is 0.1 V, when it is removed from the field in t sec. The value of t is

10 s

0.1 s

0.01 s

1 s

∈=t−(ϕ2​−ϕ1​)​=t−(0−NBA)​=tNBA​ t=∈NBA​=0.150×2×10−2×10−2​=0.1s

Q. A magnetic field of $2 \times 1 0^{- 2}$ T acts at right angles to a coil of area 100 $c m^{2}$ , with 50 turns. The average e.m.f. induced in the coil is 0.1 V, when it is removed from the field in t sec. The value of t is

$\in= \frac{- ( ϕ _{2} - ϕ _{1} )}{t} = \frac{- ( 0 - NB A )}{t} = \frac{NB A}{t}$
$t = \frac{NB A}{\in} = \frac{50 \times 2 \times 1 0 ^{- 2} \times 1 0 ^{- 2}}{0.1} = 0.1 s$