A line has slope m and y- intercept 4. The distance between the origin and the line is equal to

Question

A line has slope m and y- intercept 4. The distance between the origin and the line is equal to (A)  (4/√1-m2)  (B)  (4/√m2-1)  (C)  (4/√m2+1)  (D)  (4m/√1+m2)

Tardigrade Admin · Accepted Answer

Equation of line is y=mx+4 ∴ Required distance =(4/√1+m2)

Q. A line has slope $m$ and $y -$ intercept $4$ . The distance between the origin and the line is equal to

$\frac{4}{1 - m ^{2}}$

$\frac{4}{m ^{2} - 1}$

$\frac{4}{m ^{2} + 1}$

$\frac{4 m}{1 + m ^{2}}$

$\frac{4 m}{m - 1}$

Equation of line is $y = m x + 4$
$∴$ Required distance $= \frac{4}{1 + m ^{2}}$

Q. A line has slope m and y− intercept 4. The distance between the origin and the line is equal to

1−m2​4​

m2−1​4​

m2+1​4​

1+m2​4m​

m−1​4m​

Equation of line is y=mx+4 ∴ Required distance =1+m2​4​