A light ray of wavelength 600 nm is incident on young's double slit experiment. Distance between slits is 2 mm and 5 text th bright fringe is at a distance of 3 mm from central maxima, find the distance between slits and screen:

Question

A light ray of wavelength 600 nm is incident on young's double slit experiment. Distance between slits is 2 mm and 5 text th bright fringe is at a distance of 3 mm from central maxima, find the distance between slits and screen: (A) 20 m (B) 2 m (C) 3 m (D) 6 m

Tardigrade Admin · Accepted Answer

Given, λ = 600 nm = 600×10-9 m d = 2 mm = 2 × 10-3 m n = 5 and xn = 3 mm =3 × 10-3 m Position of nth bright fringe from central maxima is, xn = (nλ D/d)=nβ; n = 0, 1, 2, .... ⇒ 3×10-3= (5×600×10-9 D/2×10-3) ⇒ D = (3×10-3×2×10-3/5×600×10-3)=2 m

Q. A light ray of wavelength 600nm is incident on young's double slit experiment. Distance between slits is 2mm and 5th bright fringe is at a distance of 3mm from central maxima, find the distance between slits and screen:

20 m

2 m

3 m

6 m

Given, λ=600nm=600×10−9m d=2mm=2×10−3m n = 5 and xn​=3mm=3×10−3m Position of nth bright fringe from central maxima is, xn​=dnλD​=nβ;n = 0, 1, 2, .... ⇒3×10−3=2×10−35×600×10−9D​ ⇒D=5×600×10−33×10−3×2×10−3​=2m

Q. A light ray of wavelength $600 nm$ is incident on young's double slit experiment. Distance between slits is $2 mm$ and $5^{th}$ bright fringe is at a distance of $3 mm$ from central maxima, find the distance between slits and screen: